资源列表
List1
- 内有数据结构顺序表应用,顺序编码,内容准确无误。-C++ List
EX4
- SSD课程的练习4的答案,绝对正确-Exercise 4 SSD course the answer is absolutely correct
Exam2_VB
- SSD4课程的exam2的答案,绝对正确哦哦,自己做的-SSD4 exam2 course the answer is absolutely right, oh, do their own
CQueen
- //八皇后问题:在国际象棋中,能否在空格棋盘上摆放八个皇后,并使其中任意两个皇后不能在同一行或同一列或同一对角线上,编写完整的摆放八皇后问题的程序。要求:第一个皇后的起始位置由键盘输入,国际象棋的棋盘为8*8的方格。-//Eight queens problem: In chess, can be placed in the space of eight on board the Queen, the Queen can not make any two of them in the same
datastructureCodes
- 数据结构课后习题的源代码,可以拿来学习一下基础知识-After-school exercise data structure source code could be used to learn about the basics
diedaifa
- // 编程序 用迭代法求a的立方根,求立方根的迭代公式为 ::Xi+1=(2*Xi)/3+a/(3*Xi*Xi) 假定X的初值为a,迭代到|Xi+1-Xi|<10的-5次方为止. 显示a=3,27的值,并通过调用pow(a,1.0/3)函数加以验证.。-//Compile a program with Iteration Method and the cube root, find the cube root of the iteration formula is:: Xi+1 = (2*
qishixunyou
- 编写程序求解骑士巡游问题:在n行n列的棋盘上(如n=5),假设一位骑士(按象棋中“马走日”的行走法)从初始坐标位置(x1,y1)出发,要遍访(巡游)棋盘中的每一个位置一次。请编一个程序,为骑士求解巡游“路线图”(或告诉骑士,从某位置出发时,无法遍访整个棋盘 — 问题无解)。 当n=5时,意味着要在5行5列的棋盘的25个“点”处,按骑士行走规则,依次将1至25这25个“棋子”(数码)分别摆放到棋盘上(摆满25个位置则成功,否则失败问题无解)。 -Knight Parade prog
list
- 编程判断两个链表是否相交,来自微软公司的编程之美-Programming to determine whether the intersection of two lists
struct
- 数据结构(C语言版)严蔚敏_吴伟民高清扫描版,含答案-Data structure (C-language version) _ Wu Weimin Yan Wei-min scan high-definition version, with answers
shujujigoushiyanlizi
- 数据结构实验例子及指导,其中包含大约20个实验。-Experimental examples of data structure and guidance, which contains about 20 experiments.
LCS68765873568
- 求解序列的最长公共子序列问题,使用滚动数组的方法-Solve the sequence of the longest common subsequence problem, use the scroll method for array
Hoffman
- 这是我自己写的一个关于赫夫曼树及编码的建立和遍历的代码,当然不是太完美,但基本功能已经能实现。-It is my own written by a tree and codes about hoffman sentenced to establish and traversal code, of course, is not perfect, but the basic function can already achieved.
