资源列表
math
- 这是一个关于组合数学的课件，里面有各章课件及其课后答案。-This is a combination of mathematics courseware, there are chapters courseware and after-school answer.
1111
- 在visuall C++6.0环境之下开发的一个程序，有解释，K均值算法的实现-In visuall C++6.0 environment developed under a program, to explain, K-means algorithm to achieve
Research-of-Association
- 关联规则是数据挖掘的重要模式之一，有着极其重要的应用价值。本文根据关联规则挖掘的要求与特点，结合遗传算法的思想，提出了一个基于遗传算法的关联规则挖掘方法，并通过实例分析，说明是一种具有实用价值的方法。-Data mining association rules is one important model, has an extremely important value. Based on association rule mining requirements and features, c
Probability-and-Statistics-for-Engineering-and-th
- Probability and Statistics for Engineering and the Sciences Solutions
Resistor-Workshop-V1.01
- Resistor calculate and desigen circuit
fushu
- 用c++实现复数的运算，包括一个复数的乘方和绝对值运算，两个复数的加减乘除运算，以供大家参考-c++ implementation of the absolute value of complex numbers, Math and the operations of addition and subtraction of two numbers multiplied, and a number of computing power or the absolute value
guanxiyouhua
- 数据库中关系代数的优化算法，只是算法，不是完整的程序-Database optimization relational algebra, just algorithms, not the complete program
discrete_mathematics
- 离散数学，计算机中的数字为离散的，所以离散数学式计算接基础课程之一，对计算机的深入学习非常重要，是一门十分基础的课程。-discrete mathematics
Russian-farmer-algorithm
- 俄国农夫算法 俄式乘法，又被称为俄国农夫法，它是对两个正整数相乘的非主流算法。假设m和n是两个正整数，我们要计算它们的积。-Russia Russian farmer multiplication algorithm, also known as the Russian farmer method, it is multiplying two positive integers non-mainstream algorithms. Suppose m and n are two positive
rect
- 已知长方形左上角与右下角两点的坐标，求长方形面积、周长-Upper left and lower right corner of the known rectangular coordinates of two points, find the rectangular area, perimeter
SF
- 算法程序，该程序实现描述最优化的问题以及其他一般算法问题，都是AC过的，例如:最优服务分配次序的问题。-Algorithm, described the program to achieve optimization problems and other general algorithms are AC-off, such as: the optimal allocation of the order of service problems.
eight-queens
- 分治法求解八皇后问题，一个简单的分治法应用算法。-Divide and conquer method to solve the eight queens problem, a simple application of divide and conquer algorithm.