资源列表
coordinate-inverse-calculate
- 在c++语言环境下进行坐标反算，及已知边长和角度的情况下计算点的坐标-In c++ language environment carry on inverse coordinate, namely, known side length and angle then calculate points coordinates
the-nearest-point
- 算法分析实验中，用递归与分治算法实现的最接近点对实验，编程环境为vc-Algorithm analysis experiments, using a recursive divide and conquer algorithm with the nearest point of the experiment, vc++ programming environment
MASort
- 魔方阵排列算法的VC++示例源代码，用的是搜索的方法，能进行14阶以下所有魔方阵的计算任务。 -Order magic square algorithm VC++ sample source code, using a search method, can carry all of the following 14-order magic square of the computing tasks.
C-data-structures-applet
- 赫夫曼 迷宫问题 图的创建和遍历 文件的读写 文学研究助手 运动会分数统计 约瑟夫环实验报告示范及其源代码 银行业务模拟程序和作业-Huffman maze map file creation and traversal of literature to read and write scores of statistical research assistant Joseph Central Games Demonstration experiment report
Overrelaxation
- 超松弛迭代法的源代码，编译环境C++，有注释-Over relaxation method source code, build environment C++, a comment
IntegarteClass
- 一个求积分的VC++类及Demo源代码，希望对大家有所帮助-A quadrature of the VC++ Class and Demo source code, we hope to help
KSQX
- VC++递归法实现简单分形图形示例程序，比如扣氏曲线类定义等。大家在C/C++学习时都会遇到递归，课本上以汗诺塔为例进行讲解，然后大家都希望自己找到一个递归的实例。本代码以一个最简单的分形图形来示范递归的实现过程。 -VC++ recursion simple example of fractal graphics program, such as Button' s definition of curve classes. Everyone in the C/C++ will enc
Interesting-questions
- 计算不同人的国籍，很有趣的一道题。采用很精妙的算法，做出很难思考的问题-Calculate different persons， nationality, a very interesting question. Using very sophisticated algorithms, making difficult to think about
matlab
- 用蒲丰氏投针法在计算机上π值,在正方形中内切圆替换法抽样完成。-Needle with Pufeng Shi vote π value on the computer, the inscribed circle in a square in the sample to complete substitution.
fft
- 快速傅里叶变换，及其逆变换，简单易懂，从项目中转化而来，通过检测没有问题。-Fast Fourier transform, its inverse transform, easy to understand, from the project has come from no problems by testing.
Huffman_Co20319811192006.ZIP
- compresi file with huffman code
Romberg
- 这是计算方法中的一个实验，其主要功能是实现龙贝格算法-This is an experiment in the calculation, and its main function is to achieve Romberg Algorithm