资源列表
2ncimi
- 采用C语言，在visual C++6.0中实现来求2的n次方的结果-to calculate the result of n 2 multiplied
Orbit
- 卫星轨道机动模拟仿真matlab程序，应用GPS数据进行具体分析。-Matlab simulation of satellite orbit maneuver, application specific analysis of GPS data.
Digit-Overflow
- Digit Overflow summary
ant-VRP
- C++实现的VRP算法，作为实例非常不错的-C++ implementation of the VRP algorithm, as a very good example
tree
- 数据结构 二叉树 关于二叉树的各种操作 先序，中序，后续遍历-tree operation
Differential-Evolution-Algorithm
- 差分进化算法，性能很好、很热的算法。这里有C、C++、Matlab的实现，希望对大家有帮助-Differential evolution algorithm, the performance is very good, very hot algorithms. Here are C, C++, Matlab implementation, we hope to help
lementation
- 基于递归算法的树型结构图的设计实现Recursive algorithm based on tree structure of the design and implementation-Recursive algorithm based on tree structure of the design and implementation
05-StatorBarExample
- staistical wily book 05 StatorBarExample
test_vido111
- 一个基于灰度值的视频检索程序,主要是计算灰度值,对图像进行检索.-a gray value based on the video retrieval process, mainly the intensity values, the image retrieval.
Bendbolck
- 关于带通带阻滤波器的设计，巴特沃思滤波器 压缩包里有： bendpass.m 为带通程序 bendblock.m 为带阻程序 SE144.wav 采用的声音文件，请放在 C:\\下 bendpass.wav 通过带通滤波器之后的声音，保存在C:\\ bendpass.wav bendblock.wav 通过带阻滤波器之后的声音，保存在C:\\ bendblock.wav -on Bandpass Filter with the design, Butterwor
wine
- 883分酒问题，即两个8升满瓶和一个三升空瓶，无刻度，需将16升酒平均倒入四个人的口中，即每人4升酒。程序求出最小步骤及具体步骤的实现-883 hours of wine, that is two full bottles and 8 liters launched a three-bottle, no scale, the need for an average of 16 liters of wine into four individuals of the population, that
lvboqiBendbolck
- 带通和带阻滤波器的设计，包含原始信号，编码，以后仿真之后的信号-a design for filter,and including original signal and the image after simulation.