资源列表
newton
- 给定一个三次方程,用Newton法求解,并研究各种算法的收敛阶数.
FLch3LSeg1
- flch3lseg1.m二阶系统一次性完成最小二乘辨识程序
shortestpath
- 多段图的最短路径 c语言实现源代码 可以运行-A number of plans the shortest path c language source code implementation
dealsec
- VBA的判断语句以及数组的应用，可以采取动态计算以及输出单元格数值结果-VBA array to judge statements as well as applications that can take dynamic calculations and numerical results of the cell output
maze
- 实现寻找迷宫出口路径程序，可手动输入迷宫，也可随机自动产生迷宫。-Maze to find the path to achieve the export process, you can manually enter the maze, the maze can be automatically generated randomly.
CPPdoppler
- 用于计算一定速度对应的多普勒频偏，不包含对信号进行多普勒偏移的结果。-Used to calculate the Doppler shift corresponding to a certain speed, the signal does not include the results of the Doppler shift.
94
- 奇偶n阶魔方阵的实现，C语言，卡发环境VC6.0-Magic square of order n parity implementation, C language, development environment VC6.0 card
spline
- matlab三次样条插值程序，数值算法。非直接调用matlab的spline函数。-maltab spline
lvyoubeibao
- 旅游背包问题，采用近似算法BF、CF算法。题目：第i个物体大小为 Si, 箱子尺寸为c（maxSi<c). 现在有n个物体和m个箱子。请问，我们最少需要多少个箱子来储存这些物体？ 要求： 输入 文件名 输出：最少箱子数量 文件名对应的文件内容是 第一行 物体数量n 箱子尺寸C 第二行 用空格分隔的i个物体的大小 其中的数字都是整数，物体和箱子均不能分隔-Travel knapsack problem, the use of approximation algor
Test-of-statistical-significance
- 统计分析工具SAS环境下,假设检验试验源代码-Test of statistical significance.
newmark
- newmark预测校正积分 同非线性结构动力分析的newmark预测校正积分模式-newmark predictor-corrector integration
spherefiting
- this the c++ code to solve the a ball heart with the linear least Squares -this is the c++ code to solve the a ball heart with the linear least Squares