资源列表
OFDMcyclicalphaTau
- 此程序是OFDM的循环谱计算，希望对大家有用，-this procedure is the cycle OFDM spectrum, we hope to useful,
AccessDataBaseKit
- matlab的工具包，怎么用就不用我说了吧-Matlab tool kits, how it will be no need for me to say all right
AFEPack.tar
- 主要特点 * Flexible finite element space construction based template element library 基于模板单元库灵活的构造有限元空间 * Convenient facilities to implement mesh adaption 很方便的进行网格加密和稀疏化 * Multi-mesh operation supported 支持多套网格操作 需要有一定的有限元基础和C++语言
Phase-estimator
- 一篇berkeley大学Master论文 \"An Acoustic Digital Anemometer\"附带程序,Phase estimator Matlab scr ipt -a berkeley University Master's thesis on "An Acoustic Digit al Anemometer "incidental proceedings, Phase estimator Matlab scr ipt
TinySVM-0.09
- TinySVM另一種SVM的原始碼，源自於LIBSVM的另一種SVM演算法，改善LIBSVM的缺點-TinySVM another SVM source, LIBSVM originated in another SVM algorithm, improving the shortcomings LIBSVM
inclinationerr
- 经典的多点法形状复原算法的逐次2点法和逐次3点法的程序。本程序对当存在随机误差和系统误差时产生的评价误差进行了分析。-classic multi-point method shape recovery algorithm Successive 2:00 and 3:00 successive Act procedures. When the right procedures exist random error and systematic error, caused by the error
twopoint
- 经典的多点法形状复原算法中的2点法的程序。本程序用频域法和积分法2种方法复原了同一形状。数据则由csv文件读入。-classic multi-point method shape the recovery algorithm 2:00 Act procedures. The procedure uses frequency-domain law and integration methods to recover two of the same shape. Data from csv file
knapsack012
- 0/1/2背包问题,从文件输入,从文件输出.里面有详细的报告和程序说明文档-0/1/2 knapsack problem from the file input and output from the document. There are detailed reports and documentation procedures
fittingArithmeticCoding
- 自适应算术编码 C语言This package was adapted from the program in \"Arithmetic Coding for Data Compression\", by Ian H. Witten-adaptive arithmetic coding C language This package was adapted from t he program in "Arithmetic Coding for Data Compr ession &
Adaptiveimagedenoising
- 本程序由MATLAB开发，可以对图像进行小波去噪和边缘增强-the procedures developed by MATLAB, the image wavelet denoising and Edge Enhancement
ExcelCompute
- 用Excel计算代数式,代码简单易懂，解决了我的大问题啊，-algebraic expression, the code is simple to understand and solve my problem ah that the word
05060213
- lianbiao shixian bu hao yi si gang bian de-lianbiao shixian bu hao yi bian de si gang