资源列表
3D-translation
- 该程序实现了基于罗德里格矩阵的三维坐标转换，该算法简单快速，无需迭代而具有较高的精度-The program implemented based on three-dimensional coordinate transformation matrix Rodriguez, the algorithm is simple and fast, without iteration and with high precision
tuihuo-matlab
- 能够应用于多主体系统的模拟退火算法源程序，测试可用。-Multi-agent systems can be used in simulated annealing algorithm source code, testing is available.
test
- 老师布置的作业（传热学的一维稳态导热数值计算），可是有点问题，查了好几天了。可以运行，但是结果有问题。传上来希望有热心人可以帮忙看看哪里有问题，过几天还有个非稳态的，愁啊-Teacher assignments (one-dimensional heat transfer numerical steady heat conduction), but a problem, check for several days. Can run, but the results are questionab
fortran
- 结构计算程序 可求解平面钢架体系，也可用于复杂桁架体系计算-Computation program can solve plane steel frame system
newton
- 非线性方程为xe(x)括号的x为e的指数-1=0. 要求输入初值x0.和精度tol及最大循环次数N. 输出利用newton迭代法解出的近似根-Nonlinear equations for the xe (x) x as e brackets index-1 = 0. Asked to enter the initial value x0. And accuracy and the maximum number of cycles N. tol output using newton i
FFT
- 本程序是傅里叶快速算法的一个C++程序，可以了解其算法-This program is a fast algorithm for Fourier C++ program, you can understand the algorithm
QSMatrix
- C++实现的double矩阵，能够完成矩阵的+ - * / 点乘，求模，求逆等操作。-C++ implementation of the double matrix, able to complete the matrix of+-*/point multiplication, the modular, so the inverse operation.
FDTD
- 这是一个简要二全面介绍FDTD食欲有限差分法的资料，能够很快入门-FDTD
FFT
- 时间抽选基-2 FFT及IFFT算法C语言实现-Selected time base-2 FFT and IFFT algorithms C language
1
- 实现学生绩点计算，只需学生输入自己的各个科目的成绩即可算出平均绩点-Achieving students to calculate GPA
simpleCUFFT
- 基于CUDA的正反FFT实现 需要NVIDIA显卡支持-Based on the positive and negative CUDA FFT implementation needs NVIDIA graphics support
reduction_GPU
- 基于GPU的规约算法实现 需要NVIDIA显卡支持-GPU-based particle algorithm requires NVIDIA graphics support