资源列表
Client
- 插件，实例练习,主要英应用于快K3中，设计到应付应收款，金额总表-cha jian
jisuanqi
- 在计算器的设计中，加减乘除和括号功能是有优先级的，括号优先于乘除，乘除优先于加减。-In the calculator design, addition, subtraction and parentheses have priority functions, parentheses precedence over multiplication and division, multiplication and division take precedence over addition and
jiafaqi
- 改程序实现了简单的加法器功能，很容易完成加法运算。-Reform program to achieve a simple adder function, it is easy to complete the addition.
juzhenchengfa
- 利用递归进行编程，求解矩阵A的n次方代码，输入A的各元素及所计算的次方n时，即可得到计算结果-Recursive programming, solving the code matrix A ^ n
guass
- 利用高斯列主元消去法求解线性方程组Ax=b的解，并进行验证-Gauss elimination method to solve out the main element equations,
xxjs
- 一个可以随机产生两个数，进行任何四则运算，适合与小朋友学习计算时使用。-One can generate two random numbers, any four operations for calculations with the children learn to use.
preP2
- 这是利用对于ansys剖分后进行前处理的程序，以便在计算电磁学中用于计算电磁场的雷达散射截面-his is a preprocessor program,it is used to solve the RCS
Trabalho-G2---SO
- Simple Preemptive Priority Scheduling Algorithms.
POLYNOMES_EN_C
- algorithm for polynomes uses
area
- 求矩形面积：输入矩形长和宽，输出矩形面积-Seeking a rectangular area: Enter length and width of the rectangle, the output area of a rectangle
change
- 输入英文大些字母，输出小写字母，输入小写字母，输出大写字母。-Bigger input English letters, the output lowercase letters, lower case letters, uppercase output.
sales_man
- 推销员问题：穷举出推销员可能行走的每条路径，计算花费，从中选出最小的那条路径，有很详细的注释，是我们算法课的作业。-Salesman problem: a salesman may exhaustive walk each path, calculate the cost, choose the smallest piece of the path, there are very detailed notes, our algorithm homework assignment.