资源列表
fftbianhuan
- 一个c++编写的简单的FFT变换仿真曲线，进行了详细的文字说明。-A c++ write simple FFT transformation simulation curve, and carried on the detailed the text of the.
Calculator-program
- 这个例子iczelion的汇编教程24。在组装的例子，你必须有ml.exe，link.exe和nmake.exe在您的路径。如果他们不在路径，你将要编辑的文件包括完整的路径。你要编辑的文件到正确的路径导入库在您的电脑型n在同一目录中生成和装配过程将开始。-This example Iczelion compilation guide 24. During assembly of the examples, you must have ml.exe, link.exe and nmake.exe
CcoordinateTrans
- 实现坐标转化，由BJ54坐标转化为WGS84坐标，代码中的结构清晰，功能明确。-Realization of coordinate transformation from the the BJ54 coordinates converted to the WGS84 coordinate, the structure of the code is clear, a clear function.
power-flow-calculation
- 电力系统潮流计算，运用牛顿拉夫逊法对小网络进行精确地潮流计算，并进行网络损耗计算-Power flow calculation using Newton Raphson accurate flow calculation on a small network, and network loss calculation
elimination-method
- 使用列主元法求解线性方程组的通用程序，可以自己输入矩阵直接打印解向量-Use the yuan method is used to solve the list of linear equations of the general program, you can make your own input matrix print directly solution vectors
Gauss--solution-equations
- Gauss主元消去法解方程组（C语言版）-数值分析经典程序案例。-Gauss primary elimination technique solution equations-numerical analysis
equation-solved-by-Gauss-method
- Gauss主元消去法解方程组（C语言版）-数值分析经典程序案例。-Gauss primary elimination technique solution equations-numerical analysis
zhangwei019
- 这个一个是关于地震波模拟的最全面的最精确的程序代码，其中有部分我自己改了一些，不过不影响程序的整体功能-This is a seismic wave simulation which is the most comprehensive and accurate code, I have changed some part of it, but it does not affect the whole function of the program。
MMKKJJ30
- 本程序可以用于求转子系统的的临界转速问题-failed to translate
Numerical-Analysis
- 《数值分析》课的PPT，很详细很好的资料-PPT of Numerical Analysis
Matrix
- 用初等变换计算矩阵的行列式值，经过本人测试通过，想计算行列式值的可以看一下-Elementary transformation of the calculation of matrix determinant value test is passed, after I want to calculate the determinant value can look
Gauss---Seidel-iteration
- 使用高斯-赛德尔迭代求解方程组的值，是我数值分析课的作业，只能求解有唯一解情况-The value of using the Gauss- Seidel iteration for solving equations, numerical analysis homework assignment has a unique solution can only solve the