资源列表
zuixin
- dft频率测量算法，主要针对电网频率的测量-the dft frequency measurement algorithm
Pai
- 计算圆周率，精确到小数点后1600位，用400长度的整型数组变量存储-Calculate the ratio of the circumference of a circle to its diameter, accurate to one decimal 1600 with 400 length integer array variable storage
ACM_1.2.8
- Ignatius is doing his homework now. The teacher gives him some articles and asks him to tell how many times each letter appears. It s really easy, isn t it? So come on and AC ME.
ACM_1.2.7
- Do you own an ID card?You must have a identity card number in your family s Household Register. From the ID card you can get specific personal information of everyone. The number has 18 bits,the first 17 bits contain special specially meanings:the fi
cSharpyingwendanciqiufushu
- 英文单词求复数问题 编写一个程序，可以将英语规则名词（不考虑不满足以下规则的英语单词）由单数变成复数。已知规则如下： a)以辅音字母y结尾，则将y改成i，再加es； b)以s，x，ch，sh结尾，则加es； c)以元音o结尾，则加es； d)其他情况直接加s。 要求用键盘输入英语规则名词，屏幕输出该名词的复数形式。 样例输入： box 样例输出： Boxes -English words in complex problems
gsreqhcp
- 针对常水头水平渗流求解richards方程的源程序-Richards equation solving for the constant head level seepage source
gsreqvcf
- 针对非饱和土竖向常流量渗流的richard解-Richard solutions for unsaturated soil the vertical constant flow seepage
gsreqvvf
- 求解非饱和土richard方程，与上面所传为整个系统-Solving the unsaturated soil richard equation above preaching for the entire system
disanti
- 正五边形五人互相追逐，速度不同，绘图和求解最后相遇坐标的算法，matlab-The regular pentagon five people chasing each other at different speeds, drawing and solving algorithm last met coordinates, matlab
test1
- 假设有两种微生物 X 和 Y X出生后每隔3分钟分裂一次（数目加倍），Y出生后每隔2分钟分裂一次（数目加倍）。 一个新出生的X，半分钟之后吃掉1个Y，并且，从此开始，每隔1分钟吃1个Y。 现在已知有新出生的 X=10, Y=89，求60分钟后Y的数目。 如果X=10，Y=90 呢？ 本题的要求就是写出这两种初始条件下，60分钟后Y的数目。-Suppose of two microbial X and YX split time (dou
maxgap
- 给定一个随机数列，利用鸽巢原理求出数列的最大间隙-Pigeonhole principle biggest gap
test2
- 福尔摩斯到某古堡探险，看到门上写着一个奇怪的算式： ABCDE * ? = EDCBA 他对华生说：“ABCDE应该代表不同的数字，问号也代表某个数字！” 华生：“我猜也是！” 于是，两人沉默了好久，还是没有算出合适的结果来。 请你利用计算机的优势，找到破解的答案。 把 ABCDE 所代表的数字写出来。 答案写在“解答.txt”中，不要写在这里！-Sherlock Holmes adventure to a ca