资源列表
text2cass
- 度分秒转成弧度制，参与运算，得到弧度制结果，再转回度分秒输出。编程语言：C#。编程环境：VS2010-Degrees, minutes, and seconds turn into radians, participate in the operation, the radians results, and then back to degrees minutes and seconds output. Programming languages : C#. Pro
pingcha
- 解求： （1）1公里高差平差值中误差； （2）各待定点高程平差值及中误差； （3）平差后各待定点的精度；-Solutions of: (1) 1 km height difference of level difference error (2) the pending point elevation level difference in error (3) Adjustment to b
samePointMatch
- 从两幅图中找到相匹配的点的程序，可以调整搜索范围-failed to translate
APSO
- 自适应粒子群算法matlab代码,好用。-The matlab code of adptive PSO algorithm.
xianshi
- VC ++连接数据库access，存入数组-failed to translate
VOF_1D
- 一维问题的界面扑捉方法_体积分数法VOF，可以当作接近精确解使用，对刚入门比较适宜-One-dimensional interface capture method _ volume fraction method VOF, can be used as close to the exact solution to use for beginners to more appropriate
finite-voleme-method
- 界面扑捉方法_体积分数法VOF，可以当作接近精确解使用，对刚入门比较适宜-One-dimensional interface capture method _ volume fraction method VOF, can be used as close to the exact solution to use for beginners to more appropriate
knniris
- fusion svm_knn the output of svm will be the input of knn classifier
suymobile
- Calculate suy operation (develope by Bùi Thanh Dũ ng Việ t Nam)
greysystemPredict
- 灰色预测的一个代码实现，gm（1,1）模型的，mfc界面-failed to translate
fentao
- 五只猴子合作摘了很多桃子，感到累了，决定先去睡觉，醒后再分。不知过了多久，第一只猴子醒了，看见其它猴子都没有醒，就把所有桃子分为五堆，发现多一个，就吃了一个，拿走一堆，把剩下的又堆在一起走了。第2只猴子醒来，以为自己是第一个，也是把桃子分为五堆，也是多一个，就吃了一个，拿走一堆，剩下的又堆在一起走了。第3，4，5只猴子都是这样。现在问总共摘了多少桃子，每只猴子连吃再拿是多少？最后还剩多少？-Five monkeys co-picked peaches, tired and decided to
CurFit-Dichotomy
- VS2010环境，C++代码实现的：最小二乘法的多项式曲线拟合，二分法与牛顿法求多项式的解。代码清晰，可简单修改使用。经自己测试正确。-VS2010 environment, C++ code to achieve: the method of least squares polynomial curve fitting, the dichotomy Newton method for the solution of the polynomial. The code is clear and s