资源列表
caipiao
- 实现计算数字a选数字b的组合结果。程序机构简单，在matlab里面输入文件名字和组合参数就可以运行。-a select b
pr1
- #include<stdio.h> void main(void) {int n,k,derivata,a[10],i printf("n=") scanf(" d",&n) for(i=0 i<=n i++) { printf("a[ d]=",i) scanf(" d",&a[i]) } printf("k=") scanf(" d",&k) for(derivata=1 derivata<=k derivata++
ARMASA_1_9
- Features a unique program to estimate the power spectral density. The spectrum containing all significant details is calculated from a time series model. Model type as well as model order are determined automatically from the data, using statistical
Dijks-Shor-Path
- 实现了求最短路径的Dijkstra算法，方便操作，可以自已在程序界面上指定每一个点的位置，在界面上空白的地方每点击一下生成一个点-Achieved for the Dijkstra shortest path algorithm to facilitate the operation of their own in the program interface can be specified on the location of each point in the interface areas
FLCH3eg5
- 采用3-6-1型bp网络学习非线性正弦信号sin(2pi*k/50),其中2*pi/50是正弦信号的频率，k是采样次数。-Bp-based 3-6-1 network used to learn non-linear sinusoidal signal sin (2pi* k/50), which is 2* pi/50 frequency sinusoidal signal, k is the sampling frequency.
interpolacionLagrange
- this application was developed in visual c# to draw the sequence of the data given by Lagrange Interpolation algorithm
dijkstra
- tentang shortest path
LU
- LU分解算法 及 分解后矩阵解线性方程组-LU algorithm
d80
- 现在，有两个正整数A和B，例如A是345，B是478，现在，需要把B插入到A里， 而A有三位，所以有四个位置选择，所得结果分别是： 478345, 347845, 344785, 345478 我们通过对比可以知道，在这当中最小的一个是344785 这两个正整数长度不超过100000位，各个位均不包含数字0 现在的目标是，要找出插入后所能得到的最小的整数，输出这个整数 -Now, there are two positive integers A and B, for e
ch1
- 实现一个可编程表达式的计算器，并判断输入的表达式是否正确。-Expression of the realization of a programmable calculator, and determine the expression entered is correct.
GSandSOR
- 高斯GS与超松弛SOR迭代算法解线性方程组-Gaussian GS and SOR iterative algorithm over-relaxation solution of linear equations
as_2009_03_224
- some simulink of machine asynchrones