资源列表
fortran
- fortran语言的很好的学习资料，内容丰富有大量的实例。-good fortran language learning materials, a large number of instances of rich content.
Adaptive-mesh-filter
- 自适应网格滤波，里面有中文和英文的相关说明，内容很丰富，值得学习-Adaptive mesh filter, which has Chinese and English instructions, the content is very rich, worth learning
diangongjishushiyanzhidaoshu
- 电工技术实验指导书.高清晰pdf文件。用于电工的实验指导。-Experimental Results instructions
wheel-contact
- 关于轮轨接触以及轮轨乳化率的论文，非常实用，希望能够帮助大家-On the wheel-rail contact and the rate of wheel-rail emulsion paper, very useful, I hope you can help
zorandvd
- 卓然公司的966系列芯片选型，功能说明文件，文件为PDF格式。-Zoran Corporation' s 966 series chip selection, functional specification documents, the PDF format.
Computer-Vision
- 该文档是计算机视觉课程课件，介绍了计算机视觉相关领域的一些基本方法，以及前沿进展，是学习相关课程的很好的参考资料-This document is a computer vision courseware, computer vision related fields presented some of the basic methods, and cutting-edge developments related courses to learn a good reference for
EDGE_GVF-mod
- 一种GVF模型提取边缘的方法，详细介绍了关键技术和关键代码，并有应用实例-The edge of a GVF model extraction method, described in detail key technologies and key code, and application examples
CFF
- 这是一篇关于秘密共享的文章，写的不错，大家可以-This is a secret to share about the article, written well, we can see
cPPpractice
- 第6章（上）编程作业第1题题目： 1、输入一个正整数n，它代表一个人民币钱数（元数）。求取这样一个方案，使用最少张数的人民币纸币，凑成上述的钱数n。 注：共有七种元以上面值的人民币纸币，分别为：100，50，20，10，5，2，1。假设输入数据为196时， 则最少要用6张人民币纸币：196 = 1*100 + 1*50 2*20 + 1*5 + 1*1。当输入数据为908时， 则最少要用12张人民币纸币：908 = 9*100 + 1*5 + 1*2 + 1*1。 可设
ubuntu
- 本文档主要介绍ubuntu的安装和前期配置方法，对于ubuntu初学者有很大帮助-This document describes the installation and pre-configure the ubuntu way of great help for ubuntu beginners
CRC-calculation-principle
- 这是一篇论文，通用并行CRC计算原理及其硬件实现方法-CRC calculation principle of universal parallel hardware implementation
OPNET-SYNERGY
- OPNET s industry-leading solutions for Application Performance Management (APM) are the focal point for SYNERGY, including offerings that provide end-user experience monitoring and real-time application performance analytics. These solutions enab