- cchengxuyuandaima3 用程序实现二十四点的算法很多
- PLOTPAS.ZIP The latest official release of FFTW is version 3.2.1
- CR_Principles_and_Applications 认知无线电原理与应用
- Classic_Manual_of_practical_web_development web开发实用经典手册Classic Manual of practical web development
- SteamBot 登录steam账号用来交易饰品
- 51-口令模式-成功 基于51控制LD3320 口令模式语音识别(Speech recognition based on 51 control LD3320)
资源列表
CR-survey
- 认知无线电中频谱管理，动态频谱接入，认知MAC等方面的相关综述，对大家理解认知无线电技术有较好的帮助-Cognitive radio spectrum management, dynamic spectrum access, cognitive MAC overview of cognitive radio technology, for all of us to understand better help
EPM2428V120327
- EPM2428 is a new product belonging to RFIC’s EPM family. It’s a three-stage power amplifier with super high output power in 2.4-2.5GHz band utilizing InGaP/GaAs HBT process. With excellent linearity performance, the device delivers 28dBm
MFCshowimage
- MFC对话框打开一幅图片，并在picture中显示，最后保存图片，过程详尽，有图解-MFC dialog to open a picture and display it in the picture, and finally save pictures and detailed process, graphic
CPCC
- 这是cpcc的中文模板形式，大家可以下载按这个模板写发在cpcc上的论文-This is cpcc Chinese template form, you can download this template to write papers sent cpcc on
goal-detection
- 该程序是用于足球比赛中检测足球是否过球门线的检测系统-The program is used for football match detection to detect whether the football has pass the goal line
chaos
- 蔡氏混沌电路的控制，主要有线性控制，非线性控制，微分控制，等其他控制，完整的程序和方程。-Chaotic circuit control, linear control, nonlinear control, differential control, and other control, complete the procedures and equations.
example28
- 题目：有5个人坐在一起，问第五个人多少岁？他说比第4个人大2岁。问第4个人岁数，他说比第 3个人大2岁。问第三个人，又说比第2人大两岁。问第2个人，说比第一个人大两岁。最后 问第一个人，他说是10岁。请问第五个人多大？-Title: 5 people sit together, and asked the fifth person how old? He said the 2-year-old than 4 people. Ask individuals age 4, he
example22
- 题目：两个乒乓球队进行比赛，各出三人。甲队为a,b,c三人，乙队为x,y,z三人。已抽签决定 比赛名单。有人向队员打听比赛的名单。a说他不和x比，c说他不和x,z比，请编程序找出 三队赛手的名单。 -Title: two table tennis team competition, each of the trio. A team for a, b, c trio, B teams for x, y, z trio. Draw lots to decide the game
example21
- 题目：猴子吃桃问题：猴子第一天摘下若干个桃子，当即吃了一半，还不瘾，又多吃了一个 第二天早上又将剩下的桃子吃掉一半，又多吃了一个。以后每天早上都吃了前一天剩下 的一半零一个。到第10天早上想再吃时，见只剩下一个桃子了。求第一天共摘了多少。-Title: monkeys eat a peach: the first day of the monkeys picked several peaches immediately eat a half, not addiction,
convolutional-encoder
- paper from IEEE ABOUT CONVOLUTIONAL CODES
example14
- 题目：将一个正整数分解质因数。例如：输入90,打印出90=2*3*3*5。 程序分析：对n进行分解质因数，应先找到一个最小的质数k，然后按下述步骤完成： (1)如果这个质数恰等于n，则说明分解质因数的过程已经结束，打印出即可。 (2)如果n<>k，但n能被k整除，则应打印出k的值，并用n除以k的商,作为新的正整数你n, 重复执行第一步。 (3)如果n不能被k整除，则用k+1作为k的值,重复执行第一步。-Topic: the prime factors o
example11
- 题目：古典问题：有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月 后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少？-Title: Classical: one pair of rabbits, one pair of rabbits are born from the month from 3 months after birth, a small rabbit gave birth to one pair of rabbits grow up to