资源列表
hw5
- matlab code for digital communication
Encryption-Algorithm-based-on-CPP
- 分析数据加密技术中的置换算法及其加密解密思想 ,给出加密解密置换算法的程序设计方法与具体实 现步骤 ,并提供一个完整的加密解密算法的 C + + 源程序-Analysis of data encryption technology replacement algorithm and encryption and decryption of thought, given the encryption and decryption algorithms replacement program d
GMM_Examples_v2014_08_04
- GMM PARAMETERS AN BE EASILY IMPLIMENTEED USING EM TECHNIQUE.EVENTHOUGH THIS MODEL IS COMPLEX ,E XPECTATION MAXIMAISATION FINDS AN EASYWAY TO CALCULATE THE PARAMETERS IN AN EFFICIENT WAY.
RespirationPatternAnalysis
- GMM PARAMETERS AN BE EASILY IMPLIMENTEED USING EM TECHNIQUE.EVENTHOUGH THIS MODEL IS COMPLEX ,E XPECTATION MAXIMAISATION FINDS AN EASYWAY TO CALCULATE THE PARAMETERS IN AN EFFICIENT WAY.
java-programming
- java编程50题及答案，适用于java编程训练及蓝桥杯赛前练习-java programming 50 questions and answers for java programming before training exercises and Blue Bridge Cup
java-classical-algorithm
- java经典算法40题，学习算法在java中编程应用-java classical algorithm 40 questions, learning algorithms programmed in java application
基于单片机的RS232串口通信
- 基于单片机的RS232串口通信，利用SP3232进行电平转换后，通过9pin的串口进行通信
Understand-FFT-and-Windowing
- for LTE understanding FFT and windowing
Antenna-Theory-a-Design-3rd-Ed.---Balanis-Matlab-
- ALL MATLAB CODES RELATED TO ANTENNA
Unitary_esprit
- 关于面阵中二维角度估计的 Unitary -ESPRIT算法的MATLAB程序-About two-dimensional planar array of Unitary-ESPRIT angle estimation algorithm MATLAB program
3zuoye
- 某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的
twin_protocol
- Twin Protocol sample code for satellite receiver