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chuanjiaoshi
- 有3个传教士和3个野人要过河，只有一艘船，这艘船每次只能载2个人过河，且无论哪边野人的数量大于传教士的数量时，野人就会吃掉传教士。怎样让他们都安全过河？-Three missionaries and three wild man to cross the river, only one ship, the ship can only set two individuals across the river, and regardless of which side of Savage s num
River-businessmen-game
- 经典的商人过河游戏，适合有一定基础C语言的人学习-River businessmen game
across-river
- 野人传教士过河问题，采用回溯算法，可输入野人传教士人数-Savage missionaries across the river problem
CrossTheRiver
- 一个关于过河小游戏的最佳方法选择（狼人羊过河游戏）-A game about the cross-river game,calculate the best answer to sending the wolf, people and sheep to the other side of the river
cjs
- 3个传教士和3个野人过河问题matlab求解-Missionaries savage across the river problem solving matlab
shao
- 一个人,一只狼,一只山羊,一担青草,要过河,可是只有一只小船,一次只能装一个人和其他三种中的一种,请问应该怎样过河,人不在的时候,狼会吃羊,羊会吃草. -farmer across the river
YeRen
- 运用人工智能方法实现了传统的野人过河问题。-Solving the problem of savage across the river using artificial intelligence method.
Crossing-the-river-problem
- 本程序采用广度优先搜索算法求解农夫过河问题-This program uses a breadth-first search algorithm for the farmer across the river
The-merchant-across-the-river
- 一个基于C语言的益智游戏 商人过河 适合学习C语言的初学者来学习-A based on C language educational game businessman across the river learn C beginners for study
ThreadTest
- 利用java实现的一个狼羊草的过河问题。谁先过或后过，才能按要求完成-This is a problem about throughing the lake
M-C-across-the-river-problem
- 用java对野人和传教士过河问题的实现，内涵源码，传教士和野人过河是一个经典的智力难题。 希望对初学者学习java有所帮助-M with Java savage and missionaries across the river to the realization of the problem, connotation source, missionaries and savage across the river is a classic intellectual problem.
merchant_and_assistants
- 实现商人过河问题的小小的c++算法，可以计算并输出并计算每一步-Realization of merchants across the river little c++ algorithm, can be calculated and output and each calculation step
Missionaries-across-the-river
- 传教士过河问题，不仅得出可行的方案数，而且列出具体的方案。-Missionaries across the river
duhewenti
- 农夫带着狼、羊、青菜过河。 渡河问题 农夫不在时，狼会吃羊且羊会吃青菜。 每次摆渡农夫只能带一样东西。 编程显示过河方法，要求摆渡次数最少。 -农夫带着狼、羊、青菜过河。 农夫不在时，狼会吃羊且羊会吃青菜。 每次摆渡农夫只能带一样东西。 编程显示过河方法，要求摆渡次数最少。
duilie
- 使用队列的建队列,入队列和出队列的方法实现农夫过河的问题-The farmer across the river to use the build queue of the queue into the queue and the queue
dog_cat_mouse_river
- 用VHDL写的程序，模拟狗，猫，老鼠过河。规则是：狗不能跟猫单独呆在一起，老鼠跟猫不能单独在一起。-Program written in VHDL, simulated dog, cat, mouse to cross the river. The rule is: the dog can not be with the cat alone with rats and cats can not be alone together.
FRAMER
- 一个农夫带着一只羊，一条狼和一颗白菜想从河的东岸到西岸去。河上仅有一条船。只有农夫一人会开船。假设他每次只能带一只羊，或者一条狼，或者一颗白菜过河，并且当人不在场时，狼和羊，或羊和白菜不能单独在一起，因为狼会吃羊，羊会吃白菜。试编写程序求出他带一只羊，一条狼和一颗白菜过河的所有办法。-A farmer with a sheep, a wolf and a cabbage would like to go from the eastern shore of the river to the Wes
Todo-1
- TYVJ 源码（过河，但是WA不知道为什么）-TYVJ source
foxandrabbit
- 这是一个利用vc++采用简单的动画方式掩饰农民、狐狸、兔子过河的程序，与传统的狼羊过河问题是一样的。-This is a use of vc++ using a simple animation, fox, hare hide farmers across programs, and traditional wolf sheep across the river is the same.
AccrossTheRiver
- 农夫过河问题，有狼，羊，菜三种，选择安全过河方式。-The farmer across the river, there are wolves, sheep, vegetables three, select safe to cross the river way.