直接读取CD内容的程序- Straight respectfully receiveds and reads takes the CD content the procedure

poj 1451的代码和方法说明,个人原创 -the codes and solution for poj 1451

T=[1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1] 输入向量的最大值和最小值 threshold=[0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1] net=newff(threshold,[31 3],{ tansig , logsig }, trainlm ) 训练次数为1000，训练目标为0.01，学习速率为0.1

北京大学acm题库poj 1087题 一道图论题 -poj No.1451