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final.asm
- a)实现时钟功能，可以在两个七段数码管上显示秒钟时间或者分钟时间，用一个开关控制两者的切换。 b)实现闹钟功能，时间到播放一段音乐，并在发光二极管上播放走马灯图案，在双色点阵发光二极管上滚动显示自己的学号。能控制滚动显示的速度以及音乐播放的速度，且用一个开关控制闹钟的开关。-a) achieve clock function, can be in two seven-segment digital tube display seconds or minutes, with a switch
maxsize
- 稀疏矩阵采用三元组表示。 （1）求两个具有相同行列数的稀疏矩阵A和B的相加矩阵C，并输出C。 （2）求出C的转置矩阵D，输出D。-Sparse matrix expressed by triples. (1) Find the ranks of the two have the same number of sparse matrix A and B of the sum matrix C, and the output C. (2) find the C of the transp
Cellular-Neural-Network
- 细胞神经网络(CNN)是一种和人类神经网络非常相似的并行计算模型，各个邻接节点间有不同的通信。在本程序中A模型是反馈矩阵，B是控制矩阵。-Cellular neural network (CNN) is very similar to the human neural network model of parallel computation, all adjacent nodes have different communication. A model of this process is
MatrixSerialMultiply1
- c++程序分别从文件1和文件2中读取矩阵A和B，进行相乘之后将矩阵C写到文件3中.-c++ program reads matrix a and b from file1 and file2 distributedly,then run matrix multiply and get matrix c,write the matrix c into file3.
pls
- 输入自变量与因变量，输出x。y主成分、负荷及回归系数- Inputs: x x matrix y y matrix Outputs: t score for x p loading for x u score for y q loading for y b regression coefficient
pls_copy
- 这是一个非线性回归偏最小二乘程序，输入因变量与自变量，输出为x，y的主成分与负荷因子与回归系数- Inputs: x x matrix y y matrix Outputs: t score for x p loading for x u score for y q loading for y b regression coefficient
originalsimpleM111.m
- 原始单纯形法（大M法，无需给出初始基变量）。输入：C是n维行向量，A是m*n的系数矩阵，b是m维列向量 输出：x最优解（如果有的话），fval最优值，flag解的状态说明，interation求解时的循环次数-The original simplex method (big M method, without giving the initial basic variable). Input: C is the n-dimensional row vector, A is the coef
1
- 非编码键盘是利用MCS—51单片机内部的定时/计数器、中断系统、以及外围的按键和LED数码管显示等部件，设计一个单片机非编码矩阵键盘。并能通过按键实现显示0、1、2、3、4、5、6、7、8、9、A、B、C、D、E、F。-The keyboard is used non-coding MCS-51 microcontroller internal timer/counter, interrupt system and the external buttons and LED digital dis
caculator
- 利用12个按键（4*3矩阵键盘0~b，因为仅有这点按键）和一块4位七段数码管（用于显示） 能实现实数的加减乘除运算，精确至小数点后四位，并完整地显示输入及结果。 -Using the 12 keys (4* 3 matrix keypad 0 ~ b, because only this key) and a 4 segment digital tube (for display) to achieve real number addition and subtraction multi
cubesum
- Suppose there is a X x Y x Z 3D matrix A of numbers having coordinates (i, j, k) where 0 ≤ i < X, 0 ≤ j < Y, 0 ≤ k < Z. Now another X x Y x Z matrix B is defined from A such that the (i, j, k) element of B is the sum of all the the numbers i
lisanshuxushiyan3
- 以偶对的形式输入一个无向简单图的边，建立该图的邻接矩阵，判断图是否连通（A）。并计算任意两个结点间的距离（B）。对不连通的图输出其各个连通支（C）。-Even on the form to input an undirected graph edge, the establishment of the adjacency matrix to determine whether the connectivity graph (A). And calculate any distance betwe
Microsoft
- 设计一个矩阵相乘的程序，首先从键盘输入两个矩阵a，b的内容，并输出两个矩阵，输出ab－1结果。-Design a matrix multiplication of the program first and foremost from a keyboard two matrix a, b, and output two matrix and output result. ab － 1
dist
- 开车从起始点Ａ到目的地Ｂ的路线有多条。给你一张描述待选路线的表（n*n的矩阵A），让你找出行车距离最短的路线。表中表示了任意两个路口的连通情况，以及距离。矩阵元素a(i,j)=0表示路口i,j不连通，a(i,j)!=0表示路口i,j的行车距离。其中起始点Ａ在路口1，目的地Ｂ在路口n 。完成源程序DIST.CPP中Dijkstra函数的编写。-A drive to the destination from a starting point a number of B' s line. Giv
lbg
- 本程序可以将一个给定线性系统转换成龙伯格能控/能观II型。此线性系统由A,B,C,D四个矩阵描述-This program can transform a given linear system controllability Jackie Berg/observability II type. This linear system is composed of A, B, C, D four matrix descr iption
givenhousehold
- 利用该程序可计算任意对称矩阵M，给出区间(a,b)上的特征值个数-Calculated using this program any symmetric matrix M, gives the interval (a, b) on the eigenvalues
1438
- zju1438一道广度优先搜索题目，三维空间，陷阱很多。-You re in space. You want to get home. There are asteroids. You don t want to hit them. input Input to this problem will consist of a (non-empty) series of up to 100 data sets. Each data set will be formatted ac
amaterial5
- 复合材料属性矩阵A，B,D,As的确定，通过这些矩阵可以计算材料刚度矩阵-form material matrix of composite material
assign3_m100295cs
- a) On sample artificial, 8X8 / 16X16 images, take the DFT, DCT, WT, & HT. Print the image & transform matrix side by side b) Repeat the above on real images of size 256X256, and display the transform coefficients as 8-bit intensity images along
Gauss_pivot.m
- Method Gaussian Elimination without pivoting for Linear Systems Solve Ax = b using Gaussian elimination without pivoting Inputs : A is the n-by-n coefficient matrix b is the n-by-k right hand side matrix Outputs : x is the n-by-k
fconv
- FFTD(T) performs a "Dimensionless DFT" on the columns of T. T may be real or complex. T may be any size. Returns the dimensionless (unitless) vector D and the universal Basis matrix B such that- FFTD(T) performs a "Dimensionless DFT" on the