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chuankoujingling
- 所有的单片机都会涉及到232 或者485通讯,而通讯中又不可避免的出现错误.本例就给出了一个现成的校验软件.完成串口通讯,并且进行crc,累加和,异或和等效验结果-All of the single-chip will be 232 or 485 relating to communications, and communications also inevitable error. In this case on a given off-the-shelf software validatio
rightrotate
- a XOR b> a,然后a XOR b< b,and both a and b are dependent data-a XOR b
Bp_net
- 测试神经网络异或问题，只是一个很小的程序，希望大家能多多指教。-Testing neural network XOR problem, only a small fraction of the procedure, I hope we can all the exhibitions.
XOR2
- 两输入异或门 两输入异或门-Two-input XOR gate two input XOR gate
bpxor
- 用bp网络对xor问题的解析，比较基础，希望对大家有帮助-Xor network with bp analytical, comparative basis, in the hope that we have to help
DE2_VGA3
- The VGA example generates a 320x240 diffusion-limited-aggregation (DLA) on Altera DE2 board. A DLA is a clump formed by sticky particles adhering to an existing structure. In this design, we start with one pixel at the center of the screen and allow
alu
- 用VHDL实现8种运算的ALU，带鱼不带符号的加减乘除，与或异或和求反-Use VHDL to achieve the eight kinds of computing ALU, hairtail unsigned addition and subtraction, multiplication and division, with or XOR and seek anti-
mega48_HEF4070_lcddriver
- MEGA48与异或门驱动LCD+红外控制原理图 eagle编译-MEGA48 XOR gate driver with LCD+ Infrared control schematic compiler eagle
bpnn1
- 一个测试 后馈神经网络的程序, 解决XOR 问题-After a test procedure for feed-forward neural network to solve XOR problem
DelphiEnCrypt
- Delphi开发的加密解密源代码例子，利用了异或运算。-Delphi development of encryption and decryption source code examples, using the XOR operator.
EncryptByFile(clientUsing)
- VC6写的文件加密方法，其实这个比较简单，就是通过简单的异或运算进行加解密操作！13944902227-VC6 write file encryption methods, in fact, this relatively simple, that is, through a simple XOR encryption and decryption operations to carry out the operation! 13944902227
EncryptByHarddisk(clientUsing)
- VC6写的利用硬盘号加密的方法，其实这个比较简单，就是通过简单的异或运算进行加解密操作！13944902227-VC6 written using the method of hard disk encryption No. In fact, this relatively simple, that is, through a simple XOR encryption and decryption operations to carry out the operation! 139449022
EncryptByNetCard(clientUsing)
- VC6写的利用网卡加密的方法，其实这个比较简单，就是通过简单的异或运算进行加解密操作！13944902227-VC6 written card encryption method to use, in fact, this relatively simple, that is, through a simple XOR encryption and decryption operations to carry out the operation! 13944902227
AAA
- Private Sub Command1_Click() strtmp = Text1.Text nlen = Len(strtmp) k = 1 For i = 1 To nlen j = Asc(Mid(strtmp, i, 1)) If j < 47 Or j > 58 Then k = 2 End If Next i If k <> 2 Then Text2.Text = Val(Text1.Tex
CRC
- 通过对于模2除法的研究 可以得到如下方法： 1． 把信息码后面加上p－1位的0，这个试验中p是6位，即在输入的信息码后面加上“00000”。把这个17位的被除数放入input中。 2． 在得到被除数input之后，设计一个在被除数上移动的数据滑块变量d，把input中的最高位开始逐次复制给变量d。 3． 如果d的最高位为1，由变量d和变量p做异或运算；如果d的最高位为0则不运算或者做多余的异或‘0’的运算。 4． 把滑块变量d往后滑动一位。 5． 循环步骤（3，4）
asm-240128-blue-lcd-dispaly
- 辅助说明： 代码交流 QQ59771230 email:choudaxian@163.com 注意事项： 1) LCD 指令中的TEXT GRAPHIC AREA SET效果是什么样的 2) LCD 指令中的MODE SET中的OR AND XOR 有图层的味道 3) DJNZ+指令C0H(DATA AND WRITE)与相同的数据时就会出错 4) CHAR ADN PIC分别清除 5) 几何图形绘制与实现图形 6) 菜单优化设计,结构体:
demo4
- BP神经网络解决异或问题 BP神经网络解决异或问题-BP neural network to solve XOR problem of BP neural network to solve XOR problem
ALU
- 在Xilinx7.1平台下编写的ALU代码，可以实现五位加法、减法、与、异或四种运算！-Xilinx7.1 platform in the preparation of the ALU code, can be achieved five adder, subtraction, and, four computing XOR!
b
- 利用神经网络BP算法求解异或问题的源代码-The use of neural network BP algorithm XOR problem s source code
disanci
- 5位的操作数X和Y输入后暂存在寄存器A和B中，两位的操作控制码control暂存在寄存器C中，按照control码的不同，分布实现下列操作： 00控制X+Y 01控制X-Y 10控制X and Y 11控制 X xor Y 运算结果暂存在寄存器D中，然后输出。 -5 of the operand X and Y after the temporary importation of A and B in the register, the two operational c