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- System will automatically delete the directory of debug and release, so please do not put files on these two directory.
MyMessage
- 记录鼠标左键和右键单击的次数，并弹出一个对话框分别显示点击鼠标左键和右键的次数-Record the number of the left mouse button and right-click and a pop-up dialog box to display the number of times the click of the left mouse button and right-
shuju
- 北京易驰数据中心网站源码，可在线发布公告，管理企业产品（比如添加产品信息等），用户购物车管理，用户管理等。 后台管理登录：/admin_login.asp 用户名：admin 密码：admin-Beijing Yi Chi source data center sites, online announcement, enterprise management products (such as add product information, etc.), the user s
tuxingxueVC6.rar
- 主要是各种算法思想及程序，包括：直线的DDA画线、中点画线、Bresenham画线算法；中点画圆、Bresenham画圆、中点画椭圆算法；有序边表填充、种子填充、圆和椭圆的填充、图案填充算法；线型和线宽处理；Cohen-Sutherland裁剪算法、中点分割裁剪算法、Liang-Barsky裁剪算法、多边形逐边裁剪算法,AppWizard has created this Draw application for you. This application
ImagePyramidsInCPP
- It is complete c++ project for Image pyramid construction and re construction.
CSL-231_UART_Interface
- Intel R1000 UHF RFID Reader RFID_Serial_Transport_Interface_preliminary document-Intel R1000 UHF RFID Reader RFID_Serial_Transport_Interface_preliminary document
daexp3
- 音频数据的频谱分析.编程对一个wav文件（16位数据，单声道）的数据进行快速傅里叶变换，将变换后的实部和虚部数据输出至文件。-Spectral analysis of the audio data. Programming to a wav file (16 bit data, mono) data for a fast Fu Liye transform, the real and imaginary parts of the transformed data output to file.
Desktop
- 灰度直方图是灰度级的函数，描述的是图像中每种灰度级像素的个数，反映图像中每种灰度出现的频率。 -Gray level histogram is a function that describes the image gray level of each pixel number, the image reflecting the frequency of occurrence of each gray level.
TextOCR
- 通过0ffice2003识别图片中的文字，点击鼠标左键，鼠标周围的屏幕形成图片并识别其中文字-0ffice2003 identified by text in the image, click the left mouse button, the mouse around the screen to form pictures and identify which words
adsdnn
- tmlQVCD高清视频的解码器，可支持Windons各种系统-tmlQVCD high-definition video decoder that supports various system Windons
Oracle-SQL-a-PL-SQL
- 非常好用的基于oracle数据库的PLSQL教程 帮组管理和操作数据库-Very easy to use oracle database PLSQL based tutorials help group management and operation of the database
Battle-maid
- いたみ在异世界发现了一堆摞在一起的金币,每个金币都有自己的价值. 不幸的是, 因为他和一只野生女仆同时发现了这个金币堆, 所以他/她俩决定轮流拿金币. 每次每个人可以从最上面拿取1或2或3枚金币. 如果いたみ先来, 并且两人都会用最优策略, 那么いたみ最终会获得多少价值的金币? -I ta Mi in different world found a pile of gold coins stacked together, each with its own value