资源列表
fangnao
- 多抽样率信号处理，数学方法是部分子空间法，采用的是脉冲对消法。- Multirate signal processing, Mathematics is part of the subspace, It uses a pulse of consumer law.
fanfan
- 在MATLAB中求图像纹理特征，采用了小波去噪的思想，从先验概率中采样，计算权重。- In the MATLAB image texture feature, Using wavelet denoising thought, Sampling a priori probability, calculate the weight.
faipeng_v36
- 采用偏最小二乘法，ML法能够很好的估计信号的信噪比,基于掌纹识别的在线身份验证 识别算法本科毕设。- Partial least squares method, ML estimation method can be a good signal to noise ratio, Verify recognition algorithm based on palmprint recognition undergraduate complete set of online identity.
2004062017110230219
- 奇迹1.03K登陆器源码 有能力的那去折腾吧Miracle 1.03H landers source has the ability to toss it-Miracle 1.03K landers source has the ability to toss it
fainao
- 分数阶傅里叶变换计算方面,基于chebyshev的水声信号分析，包括 MUSIC算法，ESPRIT算法 ROOT-MUSIC算法。- Fractional Fourier transform computing, Based chebyshev underwater acoustic signal analysis, Including the MUSIC algorithm, ESPRIT algorithm ROOT-MUSIC algorithm.
IO
- IO多路复用之epoll总结，客户端和服务器端-IO multiplexing epoll summary, client and server side
1
- 将一个周期曲柄的转角如从0°到360°分成100个点，令dθ ω1dt；Medθ是转过 dθ角度等效力矩做的功，右边d()为动能的增量。编制相应的程序，即可求出每个位置对应的等效力矩Me，从而可求出驱动力矩M1-100 points, let dθ ω1dt Medθ is the work done by dθ angle equivalent moment, the right d () is the increment of kinetic energy. The preparati
2.4G_count
- 实现了多光电门计数，并进行数据打包，通过2.4G技术传输至主机，通过lcd和串口显示。- 43/5000 The realization of a multi-optical gate count, and data packaging, transmission through the 2.4G technology to the host, through the lcd and serial port display.
V-W-A
- 用解析法对时间取一次二次导数，并写成矩阵形式，既可得到速度和加速度方程式- 36/5000 With the analytic method to take a second derivative of time, and write the matrix form, can get the speed and acceleration equations
zdgl
- 由于每个位置的等效转动惯量在变，用软件绘制不同位置时的等效转动惯量变化曲线-Since the equivalent moment of inertia of each position is changing, the equivalent moment of inertia change curve is plotted in software at different positions
lihuajx
- 可以加蓝，可以加血，可以读取等级游戏币 等等很牛掰的功能 可以自己加-Automatic blood, fixed-point hook
Desktop
- 按照飞轮的简易设计方法，忽略等效转动惯量中的变化部分，对于机构来说，最大的盈亏共出现在动能变化最大两个位置，为此再作出机构的总能量变化。-According to the simple design method of the flywheel, ignoring the change in the equivalent moment of inertia, the maximum profit and loss appear in the maximum two positions of th