现有16位寄存器。初始值为0。每个时钟周期寄存器的值会左移1位，并且将输入的数据data_in作为寄存器的最低位，寄存器原来的最高位将被丢弃。要求每个周期实时输出该16位寄存器对7求余的余数data_out[20]。(Existing 16 bit register. The initial value is 0. The value of each clock cycle register will shift 1 bit to the left, and the input data will be_ In as the lowest bit of the register, the original highest bit of the register will be discarded. It is required to output the remainder data of the 16 bit register to 7 in real-time in each cycle_ out[20].)