资源列表
hubo
- 人脸识别设计包括所需要的函数 用Matlab实现的
labe_forOpencv
- 本例使用了opencv中图像数据结构IplImage ：首先进行第一次扫描，标记连通区域；然后对等价标记进行合并，最后进行第二次扫描，对等价标记进行重新标记。-This example uses a data structure of the opencv: IplImage. First, scan for the first time, marking connected region then mark the merger of the equivalence, and final
CrazyLine
- topcoder 694题目A rigorous teacher makes all his students stand in a line before entering the classroom. Being a rigorous teacher, he makes the students line up in non-descending order by height. One time, while the students were lining up, the teacher
bahaunghou
- 皇后问题实现，以棋盘的形式展示，并且输出可行结果-the completeof queen question
bzpyj
- 可在用户坐标系下标示选取点的绝对坐标。 技巧：（按一下F8键试试，你可能会有一点惊喜哟） 如果有什么BUG，请联系我：piaoyj@szmedi.com.cn 启动命令为zb-Select the points can be marked in the user coordinate system absolute coordinates. Skills: (click the F8 key to try, you may have a little surprise y
ColorPlane
- Geometry频繁改变颜色总是有问题，这样就没事了-Geometry frequent changes color is always a problem, so all right
Fibonacci
- 斐波那契数列Fibonacci Sequence的Java语言呈现-Fibonacci number Fibonacci sequence Java language presentation
haarfd
- 调用笔记本和外接摄像头的双目摄像人脸识别，基于opencv-dual webcam face detection
Motion
- 教程3交互使用GLUT 运动回调演示，还演示像素的复制和像素变焦-Tutorial 3 interactive presentations using GLUT callback campaign, also demonstrates copy pixels and pixel zoom
edgedetection
- opencv实现的图像边界快速检测，找出图像各轮廓-opencv image boundaries to achieve rapid detection, to identify each contour image
MatrixChain
- 实验二-矩阵链乘 Descr iption 给定n个矩阵A1，A2，…，An，其中，Ai与Aj+1是可乘的，i=1，2，…，n-1。 你的任务是要确定矩阵连乘的运算次序，使计算这n个矩阵的连乘积A1A2…An时总的元素乘法次数达到最少。 例如：3个矩阵A1，A2，A3，阶分别为10×100、100×5、5×50，计算连乘积A1A2A3时按（A1A2）A3所需的元素乘法次数达到最少，为7500次。-MatrixChain dp
region_growing
- 比较简单区域增长算法对dicom数据进行分割，注释详尽，适合初学者学习-segment image with region growing for dicom data