资源列表
QuartusHandbook
- QuartusII软件的使用手册，版本是QuartusII7.2，希望对大家有帮助。-QuartusII software manual, version QuartusII7.2, we want to help.
clock
- 时钟设计 实现钟表功能可自动调节时间的大小以及充当秒表-Clock design and implementation of time clocks feature automatically adjusts the size and act as a stopwatch
stm
- 用verilog语言设计一个二进制序列检测电路， 当输入有连续“1011”出现时有输出为‘1’， 否则为‘0’.-Verilog language used to design a binary sequence detection circuit, a continuous input " 1011" appears when the output is ' 1 ' , otherwise ' 0' .
xilinxhelp1
- this is xilinx help guide
seg71
- ７段数码管测试实验１：以动态扫描方式在８位数码管“同时”显示０--7 实验的目的是向用户介绍多个数码管动态显示的方法。 动态显示的方法是，按一定的频率轮流向各个数码管的COM端送出低电平，同时送出对应的数据给各段。-7-segment test experiment 1: 8-bit dynamic digital scanning mode in the pipe " while" display 0- 7 experiment is introduced to th
key1
- 矩阵键盘实验1：向用户介绍矩阵键盘扫描实现的方法，没有考虑去抖和判断键弹起的问题；把相应的键值显示在数码管上-Matrix Keyboard Lab 1: Introduction to the user to achieve the keyboard scan matrix approach, not considered to shake and bounce to determine key issues the corresponding keys on the display in
ledwater
- 跑马灯实验：利用计数器轮流点亮LED灯，实现各种动态效果。 -Marquee experiment: the use of counter rotating light LED lights, to achieve a variety of dynamic effects.
bcd
- 4位二进制数转BCD码，由拨码键盘输入，结果由数码管显示-BCD 4-bit binary code switch from dial code keyboard input, the results from the digital display
state_machine
- 简单的状态机，有8个状态,数码管输出当前状态的编号 state0--state1--state2--state3--state4--state5--state6-state7--state0-Simple state machine with 8 states, the digital output of the current state of the number state0- state1- state2- state3- state4- state5- state6-state7
quanjianqi
- 本源码的作用是简单地实现一位二进制的全减-The role of the source is simply a binary realization of the full reduction
FIFOMXN
- 该VHDL描述的是一个简单的先进先出存储器-a first-in first out memory, uses a synchronising clock generics allow fifos of different sizes to be instantiated
8multipler
- 用VHDL实现8位移位相加乘法器，从被乘数的最低位开始，若为1，则乘数左移后与上次的和相加；若为0，左移后以全0相加，直至被乘数的最高位。-VHDL 8-bit shift by adding the multiplier to achieve, starting from the lowest multiplicand, if 1, then left after the multiplier and add the last if 0, left after adding all 0, u